Cedar Grove, Florida

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Cedar Grove is a town in Bay County, Florida, United States. The population was 5,367 at the 2000 census.

Geography

Cedar Grove is located at [30°12′44″N, 85°36′22″W] (30.212219, -85.606028)^{[Geographic references#1GR1]}.

According to the United States Census Bureau, the town has a total area of 24.3 km² (9.4 mi²), all land.

Demographics

As of the census^{[Geographic references#2GR2]} of 2000, there were 5,367 people, 2,109 households, and 1,423 families residing in the town. The population density was 220.9/km² (572.5/mi²). There were 2,341 housing units at an average density of 96.4/km² (249.7/mi²). The racial makeup of the town was 85.47% White, 9.60% African American, 0.73% Native American, 1.77% Asian, 0.09% Pacific Islander, 0.56% from other races, and 1.79% from two or more races. Hispanic or Latino of any race were 2.11% of the population.

There were 2,109 households out of which 34.6% had children under the age of 18 living with them, 46.7% were married couples living together, 16.2% had a female householder with no husband present, and 32.5% were non-families. 26.4% of all households were made up of individuals and 7.4% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 3.00.

In the town the population was spread out with 27.2% under the age of 18, 9.9% from 18 to 24, 29.4% from 25 to 44, 20.7% from 45 to 64, and 12.9% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 92.4 males. For every 100 females age 18 and over, there were 87.3 males.

The median income for a household in the town was $28,762, and the median income for a family was $31,577. Males had a median income of $25,203 versus $18,250 for females. The per capita income for the town was $13,588. About 16.1% of families and 19.0% of the population were below the poverty line, including 29.8% of those under age 18 and 7.1% of those age 65 or over.

External links

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