Derivation of the cartesian formula for an ellipse
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The derivation of the cartesian form for an ellipse is simple and instructive. An ellipse is defined as a the loci of points equidistant to two fixed points called the foci. Assuming that the foci are located at (-c,0) and (c,0) (ie. the ellipse is centered at (0,0)) then the sum of the distance between any point (x,y) and the two foci is constant.
If (x,y) is any point on the ellipse and if [d_1] is the distance between (x,y) and (-c,0) and [d_2] is the distance between (x,y) and (c,0), i.e.
- [d_1 = \sqrt ]
- [d_2 = \sqrt ]
- [d_1 + d_2 = 2a]
- [\sqrt + \sqrt = 2a]
- [\sqrt = 2a - \sqrt ]
- [(x+c)^2 + y^2 = \left ( 2a - \sqrt \right )^2]
- [(x+c)^2 + y^2 = 4a^2 - 4a\sqrt + (x-c)^2 +y^2]
- [\sqrt = - ((x+c)^2+y^2-4a^2-(x-c)^2-y^2) ]
- [\sqrt = - (x^2 + 2xc + c^2 -4a^2 -x^2 +2xc -c^2)]
- [\sqrt = - (4xc - 4a^2)]
- [\sqrt = a - x]
- [(x-c)^2+y^2 = a^2 - 2cx + x^2]
- [x^2 - 2xc + c^2 + y^2 = a^2 -2xc + x^2]
- [x^2 + c^2 + y^2 = a^2 + x^2]
- [x^2 \left( 1 - \right) + y^2 = a^2 - c^2]
- [x^2 \left( \right) + y^2 = a^2 - c^2]
- [ + = 1]
Therefore we can substitute
- [b^2 = a^2-c^2]
- [ + = 1]
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