Directional Stability
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Directional stability is the tendency of a moving body to align itself with the direction of motion.
With the exception of spacecraft, vehicles generally have a recognisable front and rear and are designed so that the front points more or less in the direction of motion. Without this stability, they may tumble end over end, spin or orient themselves at a high angle of attack, even broadside on to the direction of motion. At high angles of attack, drag forces may become excessive, the vehicle may be impossible to control, or may even experience structural failure. In general, land, sea, air and underwater vehicles are designed to have a natural tendency to point in the direction of motion.
Arrows, darts, rockets and airships have tail surfaces to achieve this. A road vehicle does not have elements specifically designed to maintain stability, but relies primarily on the distribution of mass.
Example - Road Vehicle
Introduction
The first stage of studying the stability of a road vehicle is the derivation of a reasonable approximation to the equations of motion.
The diagram illustrates a four wheel vehicle, in which the front axle is located a metres ahead of the centre of gravity and the rear axle is b metres aft of the cg. The body of the car is pointing in a direction [\theta] (theta) whilst it is travelling in a direction [\psi] (psi). In general, these are not the same. The tyre treads at the region of contact point in the direction of travel, but the hubs are aligned with the vehicle body, with the steering held central. The tyres distort as they rotate to accommodate this mis-alignment, and generate side forces as a consequence.
The net side force Y on the vehicle is the centripetal force causing the vehicle to change direction:
- [MV \frac =Y cos(\theta-\psi)]
- [MV\frac=Y ]
- [I\frac=N ]
- [\phi(front)=\theta-\psi-\frac\frac]
- [\phi(rear)=\theta-\psi+\frac\frac]
- [Y=2k(\phi(front)+\phi(rear))=4k(\theta-\psi)+2k\frac\frac]
- [N=2k(a\phi(front)-b\phi(rear))=2k(a-b)(\theta-\psi)-2k\frac\frac]
- [\frac=2k\frac(\theta-\psi)-2k\frac\omega]
- [\frac=\omega]
- [\frac=\frac(\theta-\psi)+2k\frac\omega]
- [\frac=2k\frac\beta-2k\frac\omega]
- [\frac=-\frac\beta+(1-2k\frac\omega]
- [\frac+(\frac+\frac)\frac+(\frac+\frac)\beta=0]
We do not need to solve it explicitly to decide whether the solution diverges indefinitely or converges to zero following an initial perturbation. The form of the solution depends on the signs of the coefficients.
The coefficient of [\frac] will be called the 'damping' by analogy with a mass-spring-damper which has a similar equation of motion.
By the same analogy, the coefficient of [\beta] will be called the 'stiffness', as its function is to return the system to zero deflection, in the same manner as a spring.
The form of the solution depends only on the signs of the damping and stiffness terms. The four possible solution types are presented in the figure.
The only satisfactory solution requires both stiffness and damping to be positive.
The damping term is:
- :[(\frac+\frac)]
The stiffness term is:
- :[(\frac+\frac)]
- :[V^2=\frac]
Relative Effect of Front and Rear Tyres
If for some reason (incorrect inflation pressure, worn tread) the tyres on one axle are incapable of generating significant lateral force, the stability will obviously be compromised. Assume to begin with that the rear tyres are faulty, what is the effect on stability?
If the rear tyres produce no significant forces, the side force and yawing moment become:
- [Y=2k(\phi(front))=2k(\theta-\psi)-2k\frac\frac]
- [N=2k(a\phi(front))=2ka(\theta-\psi)-2k\frac\frac]
- [\frac+(\frac+\frac)\frac-(\frac)\beta=0]
- [Y=2k(\phi(rear))=2k(\theta-\psi)+2k\frac\frac]
- [N=-2k(b\phi(rear))=-2kb(\theta-\psi)-2k\frac\frac]
- [\frac+(\frac+\frac)\frac+(\frac)\beta=0]
It follows that the condition of the rear tyres is more critical to directional stability than the state of the front tyres.
Steering Forces
Deflecting the steering changes the slip angle of the front tyres, generating a sideforce. With conventional steering, the tyres are deflected by different amounts, but for the purposes of this analysis, the additional slip will be considered equal for both front tyres.
The side force becomes:
- [Y=2k(\phi(front)+\phi(rear))=4k(\theta-\psi)+2k\frac\frac+2k\eta]
- [N=2k(a\phi(front)-b\phi(rear))=2k(a-b)(\theta-\psi)-2k\frac\frac+2ka\eta ]
- [\frac+(\frac+\frac)\frac+(\frac+\frac)\beta=-\frac\frac+(\frac-\frac)\eta]
- :[(\frac-\frac)]
- :[V^2=\frac]
As an example:
- :with k=10kN/radian, M=1000kg, b=1.0m, a=1.0m, the vehicle understeers below 11.3mph.
Limitations of the Analysis
The forces arising from slip depend on the loading on the tyre as well as the slip angle, this effect has been ignored, but could be taken into account by assuming different values of k for the front and rear axles. Roll motion due to cornering will redistribute the tyre loads between the nearside and offside of the vehicle, again modifying the tyre forces. Engine torque likewise re-distributes the load between front and rear tyres.
A full analysis should also take account of the suspension response.
The complete analysis is essential for the design of high performance road vehicles, but is beyond the scope of this article.
References
- Barwell F T : Automation and Control in Transport, Pergamon Press, 1972.
- Synge J L and B A Griffiths : Principles of Mechanics, Section 6.3, McGraw-Hill Kogakusha Ltd,3rd Edition, 1970.
See also
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