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Indecomposable distribution

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In probability theory, an indecomposable distribution is any probability distribution that cannot be represented as the distribution of the sum of two or more non-constant independent random variables.

Examples

:[X = \left\1 & \mathrm\ \mathrm & p, \\0 & \mathrm\ \mathrm & 1-p,\end\right.]
then the probability distribution of X is indecomposable.
:[X = \left\2 & \mathrm\ \mathrm\ a, \\1 & \mathrm\ \mathrm\ b, \\0 & \mathrm\ \mathrm\ c.\end\right.]
This probability distribution is decomposable if
:[\sqrt + \sqrt \le 1 \ ]
and otherwise indecomposable. To see, this, suppose U and V are independent random variables and U + V has this probability distribution. Then we must have
:[\beginU = \left\1 & \mathrm\ \mathrm & p, \\0 & \mathrm\ \mathrm & 1 - p,\end\right.& \mbox &V = \left\1 & \mathrm\ \mathrm & 1, \\0 & \mathrm\ \mathrm & 1 - q,\end\right.\end]
for some p, q ∈ [0, 1]. It follows that
:[a = pq, \, ]
:[c = (1-p)(1-q), \, ]
:[b = 1 - a - c. \, ]
This system of two quadratic equations in two variables p and q has a solution (pq) ∈ [0, 1]2 if and only if
:[\sqrt + \sqrt \le 1. \ ]
Thus, for example, the discrete uniform distribution on the set is indecomposable, but the binomial distribution assigneing respective probabilities 1/4, 1/2, 1/4 is decomposable.
:[f(x) = } x^2 e^]
is indecomposable.
:[ \sum_^\infty , ]
where the independent random variables Xn are each equal to 0 or 1 with equal probabilities.
:[\Pr(Y = y) = (1-p)^n p\, ]
on . For any positive integer k, there is a sequence of negative-binomially distributed random variables Yj, j = 1, ..., k, such that Y1 + ... + Yk has this geometric distibution. Therefore, this distribution is infinitely divisible. But now let Dn be the nth binary digit of Y, for n ≥ 0. Then the Ds are independent and
:[ Y = \sum_^\infty , ]
and each term in this sum is indecomposable.

References

 


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